PS9-08-Solution - Chem 442 Homework Set #9 DUE: Tuesday,...

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Chem 442 Homework Set #9 DUE: Tuesday, November 18, 2008 1) McQ&S, 9-15 2 g s σ * 2 u s 2 u p π 2 g p * 2 g p * 2 u p 2 C 2 g s * 2 u s 2 u p 2 g p * 2 g p * 2 u p 2 C () 2 2 2 1 Bond Order= number of bonding electrons -number of antibonding electrons 2 :..2 . 5 As bond order increases, bond strength increases and bond length decreases. C has a larger bond strength a CB O O = = 2 nd a smaller bond length than C . 2) McQ&S, 9-17 2 s * 2 s 2 p 2 p * 2 p * 2 p NO NO + 2 s * 2 s 2 p 2 p * 2 p * 2 p ( ) 21 24 2 ** 2 2 * :2 2 2 2 2 . . 2 2 2 . . 3 .. NO NO NO KK s s p p p B O NO KK s s p p B O BO σσ + + →= < 2 . 5 Problem Set #9 - Solutions - 1 -
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3) McQ&S, 9-23 () ( ) 34 8 18 9 electron 18 max 6.626 10 3 10 / 3.40 10 58.4 10 Largest binding that can be measured would be when KE 0 which gives 3.40 10 Sending photon electron photon binding binding photon Js ms hc EJ m KE E E EE J λ ×⋅ × == = × × =− = × in the photons will result in the ionization of the molecule. By measuring the kinetic energy of the electrons coming off, we can deduce the binding energy of the electrons.
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This note was uploaded on 02/12/2011 for the course CHEMISTRY 442 taught by Professor Lizzy during the Spring '10 term at Hanoi University of Technology.

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PS9-08-Solution - Chem 442 Homework Set #9 DUE: Tuesday,...

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