PS10-08-Solution - Chem 442 Homework Set #10 DUE:...

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Chem 442 Homework Set #10 DUE: Wednesday, November 19, 2008 1) McQ&S, 10-18 2 CO Linear 2 CO + Linear 2 CF Bent 2) McQ&S, 10-20 Since this orbital has no dependence on the bond angle, it must be a core orbital. So, the 1a 1 is just the 1s orbital on X. Since this orbital is a core orbital, it is not involved in bonding and therefore, the bond angle will have no impact on the energy of this orbital. 3) McQ&S, 10-23 3 Planar BH 3 Not Planar CH Problem Set #10 - Solutions - 1 -
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3 Not Planar CH 3 Not Planar NH Don’t forget that the 1a orbital represents the 1s orbital on the central atom. 4) The lowest energy electronic transitions in ethene (C 2 H 4 ) and benzene (C 6 H 6 ) occur at 28,700 and 29,510 cm -1 , respectively. Using Hückel theory, determine the value of β (in cm -1 ) for both molecules (assuming that the lowest energy electronic transition in each molecule occurs between the highest occupied and lowest unoccupied π orbital). How well did Hückel theory work, i.e., are your two values for β similar?
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This note was uploaded on 02/12/2011 for the course CHEMISTRY 442 taught by Professor Lizzy during the Spring '10 term at Hanoi University of Technology.

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PS10-08-Solution - Chem 442 Homework Set #10 DUE:...

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