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Unformatted text preview: And again, the product of the 3 numbers on the last diagonal . Now beginning with the 1 in the upper right hand corner, we are going to come back, multiplying the numbers on the diagonals. We will also sum these and then subtract the answer from the sum above. 1 1 1 3 1 2 2 1 1 4 1 3 1 2 1 1 1 3 1 2 2 1 1 4 1 3 1 2 1(3)(2) ) )( ( 1 4 2 + 14 8 6 1 1 = + + =+ ) )( ( Now subtract: 0  14 =  14 (2)(1)( 2) + (1)(4)(1) +(0)(3)(1)=4+4+0=0...
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 Spring '11
 Yuan
 Linear Algebra, Algebra, Determinant, Multiplication, Matrices, Characteristic polynomial, short cut methods

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