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Unformatted text preview: And again, the product of the 3 numbers on the last diagonal . Now beginning with the 1 in the upper right hand corner, we are going to come back, multiplying the numbers on the diagonals. We will also sum these and then subtract the answer from the sum above. 1 1 1 3 1 2 2 1 1 4 1 3 1 2 1 1 1 3 1 2 2 1 1 4 1 3 1 2 1(3)(2) ) )( ( 1 4 2 + 14 8 6 1 1 = + + =+ ) )( ( Now subtract: 0  14 =  14 (2)(1)( 2) + (1)(4)(1) +(0)(3)(1)=4+4+0=0...
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This note was uploaded on 02/13/2011 for the course MAT 3321 taught by Professor Yuan during the Spring '11 term at Texas Wesleyan.
 Spring '11
 Yuan
 Linear Algebra, Algebra, Determinant, Matrices

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