Extra credit - on the circle. d/v will be time taken by...

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Bobby Mesa CSC1310 Extra credit Three Switches Turn on two switches, leave the other off. Wait a while then turn off one of the two switches. The light that’s on is the switch you flipped once. The light that is off and still warm is the switch you flipped twice. The last one is the one you never touched. Heavy Marble Two turns. Take six of the marbles and put three on each side. Two things could happen, one is the scale is even, if so place the remaining two on the scale and the one that tips is the heaver one. If the scale does tip then reweigh two of the three marbles. Again two things could happen, a tip which would show the heaver one, or it could be even leaving the heaver one left out. (n/3)/3 The Fox and Duck Let’s assume the radius of the pond is R, max speed of duck in water is v, and max speed of fox on land is 4v. d is the distance for duck to reach the edge and assume the fox is on exactly opposite side
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Unformatted text preview: on the circle. d/v will be time taken by duck to reach edge whereas pi*R/4v will be time taken by fox to reach the same point For duck to reach safely at edge d/v <= pi*R/4v that is d <= (pi/4)*R If duck starts circling in the pond exactly at distance d1 then 2*pi*d1/v <= 2*R/4v therefore the duck should start circling at d1 radius = R/4. Bobby Mesa CSC1310 Extra credit Now if duck reduces the circling radius even slightly, the possibility of living fox behind will increase. When the fox and duck are exactly opposite, the duck can start swimming towards edge. Now, the remaining distance to edge is (3/4) R. as the remaining distance is (3/4)R is lesser then (pi/4)R. The duck can reach edge safely and fly. For duck to start swimming towards edge from a point d distance from Edge and assume the fox is exactly opposite the duck....
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Extra credit - on the circle. d/v will be time taken by...

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