13 FoC Activation Energy

13 FoC Activation Energy - Learning from last time: predict...

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1 1 Learning from last time: predict a rate law! What is the rate law predicted by the following mechanism for the reaction Cl 2 + CO COCl 2 assuming that equilibrium is established in both Steps 1 and 3. Step 1 fast: Cl 2 + CO COCl + Cl Step 2 slow: COCl + Cl 2 COCl 2 + Cl Step 3 very fast: Cl + Cl Cl 2 A) Rate = k[Cl 2 ] 3/2 [CO] B) Rate = k[COCl][Cl 2 ] C) Rate = k[Cl] 2 [CO][Cl] -1 D) Rate = k[Cl 2 ][CO] 2 Solution to Problem #2. Step 1 fast: Cl 2 + CO COCl + Cl Step 2 slow: COCl + Cl 2 COCl 2 + Cl Step 3 very fast: Cl + Cl Cl 2 ] [ ] [ / ] [ ] [ : ] [ ] [ : 3 ] [ ] ][ [ ] [ : ] ][ [ ] ][ [ : 1 ] ][ [ k' 2 2 / 3 2 2 / 1 3 2 / 1 2 2 2 3 2 1 2 1 2 CO Cl k Rate So K Cl Cl Substitute Cl Cl K m Equilibriu Step Cl CO Cl K COCl Substitute CO Cl Cl COCl K m Equilibriu Step Cl COCl Rate Step eq eq eq eq
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2 5 Scores on Exam 1 0 20 40 60 80 100 120 0 1 02 03 04 05 06 07 08 09 0 Pecent Score Number of Students Mean = 70 85 A 70 B 55 C Percent score = number correct x 5 8 I scored below 55 on the exam, what should I do? Look at each question that you missed, identify why you missed it and what you should have done to do better. Arrange to meet with Professor Hanson if you want to discuss these insights or gain others. Review the material in Lecture 1 and in the paper on a cognitive model for learning chemistry and solving problems to help you understand what you need to do to do better. Follow the General Chemistry Learning Cycle presented in Lecture 2 that is based on this research. In solving problems understand why certain concepts are used and why each step is done .
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3 9 For everyone Exam scores tend to go down as the semester progresses.
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13 FoC Activation Energy - Learning from last time: predict...

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