Ch 14 Answers - 1 Ch. 14. Extra Problem Answers 1. (Both...

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Ch. 14. Extra Problem Answers 1. (Both must be right for each structure to get any points) N S N N H H + N H # π electrons: ___6 __ ____8 _____ ____2 _____ ____10 ____ aromatic: __Y___ ____N_____ ____Y_____ ____Y_____ (Y(es) or N(o)) (Assume planar nitrogens for the second structure from the left above above and third below) Since neither compound would be aromatic if the N atoms were planar (8e π system), they actually have significantly pyramidal N’s, to avoid being “anti-aromatic”. There is significant overlap of even an sp 3 lone pair with the π system. N N CH 3 + N O H # π electrons: ___6 __ ____6_____ ____8_____ ____8 ____ aromatic: __Y___ ____Y_____ ____N_____ ____N_____ (Y(es) or N(o)) 2. Finish the sketches below. Add the hydrogens and C-H sigma bonds (just draw them as lines), draw in all p and lone pair orbitals, and put electrons in as the proper number of dots in the proper orbitals. Label each lone pair orbital that is perpendicular to the aromatic π system “LP”. imidazole
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This note was uploaded on 02/14/2011 for the course ORGANIC CH 341 taught by Professor Idk during the Spring '11 term at Wisconsin.

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Ch 14 Answers - 1 Ch. 14. Extra Problem Answers 1. (Both...

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