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Unformatted text preview: 1 Phys 1L03 Tutorial session Set Practice Key: Answers and some hint fro set Practice Problems 1. ∑ = = a m F F i t e n x x t e n F N F x − = , : f g m F F y y y t e n ± − = , : 07 . 7 45 sin = = F F y N g m 8 . 9 = y F g m > Q Block is to move downward. But we have friction. So the friction is upward F F F N x 7 . 45 cos = = = N N f s Max y 9 . 4 , = = μ Max S y f F g m , < − Q The wood block stays at rest. 2. Positive x direction. 3. Draw free body diagram : 4. kg m 10 = 1 . = k μ N f k k μ = = − w N N g m w N 98 = = = ⇒ N f k 8 . 9 = ∴ 5. a m F t e n = box box k a m f = ⇒ box a kg N ) 10 ( 10 = ⇒ 2 / 1 s m a box = 6. ) ( ) ( truck on car car on truck F F ⇔ 7. a. b . 8. The force of the 1 kg block on the rope 9. The acceleration is 1.8 m/s 2 to the left. The magnitude of the two acceleration should be equal 2 We may calculate the acceleration: Consider the two free body diagrams at question 7: ⎩ ⎨ ⎧ = − = − − − a m f T a m f f T F 1 1 2 2 1 The acceleration for both blocks is the same. The acceleration for both blocks is the same....
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This note was uploaded on 02/14/2011 for the course PHYS 1L03 taught by Professor Hughes during the Spring '11 term at McMaster University.
 Spring '11
 HUGHES
 Physics, Acceleration

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