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Timepass - double y2 = in.nextDouble double x =(x1-x2...

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import java.util.*; i public class Timepass{ public static void main(String []args){ int annoy; annoy=200; Scanner in = new Scanner(System.in); System.out.println("Please enter x coordinate of the point 1"); double x1 = in.nextDouble(); System.out.println("Please enter y coordinate of the point 1"); double y1 = in.nextDouble(); System.out.println("Please enter x coordinate of the point 2"); double x2 = in.nextDouble(); System.out.println("Please enter y coordinate of the point 2");
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Unformatted text preview: double y2 = in.nextDouble(); double x = (x1-x2); double y = (y1-y2); double result = Math.sqrt((x*x)+(y*y)); //double result2 = ((Math.PI)*2*s); System.out.println("distance between the 2 points is: "+result); //System.out.println("Circumference of the circle is: "+result2); while(true){ System.out.println("Aashay is still a fag"); try{ Thread.sleep(annoy); } catch(Exception e){} } } }...
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