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Hw8_Sol

# Hw8_Sol - Math464 HW 8 Due on Tuesday Mar 23 1 Linear...

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Unformatted text preview: Math464 - HW 8 Due on Tuesday, Mar 23 1 Linear Optimization (Spring 2010) Brief solutions to Homework 8 1. The simplex method with default rules cycles (Table 1). Table 1: Simplex with default rules (Problem 1). rhs x 1 x 2 x 3 x 4 x 5 x 6 x 7- 10 57 9 24 x 5 = 1 / 2- 11 / 2- 5 / 2 9 1 x 6 = 1/2- 3 / 2- 1 / 2 1 1 x 7 = 1 1 1- 53- 41 204 20 x 1 = 1- 11- 5 18 2 x 6 = 4 2- 8- 1 1 x 7 = 1 11 5- 18- 2 1- 29 / 2 98 27/4 53/4 x 1 = 1 1 / 2- 4- 3 / 4 11/4 x 2 = 1 1/2- 2- 1 / 4 1/4 x 7 = 1- 1 / 2 4 3/4- 11 / 4 1 29- 18-15 93 x 3 = 2 1- 8- 3 / 2 11/2 x 2 =- 1 1 2 1/2- 5 / 2 x 7 = 1 1 1 20 9- 21 / 2 141/2 x 3 =- 2 4 1 1 / 2- 9 / 2 x 4 =- 1 / 2 1/2 1 1/4- 5 / 4 x 7 = 1 1 1- 22 93 21- 24 x 5 =- 4 8 2 1- 9 x 4 = 1/2- 3 / 2- 1 / 2 1 1 x 7 = 1 1 1- 10 57 9 24 x 5 = 1 / 2- 11 / 2- 5 / 2 9 1 x 6 = 1/2- 3 / 2- 1 / 2 1 1 x 7 = 1 1 For the lexicographic pivoting rule (Table 2), we could use the same criterion for the entering variable the non-basic variable with the most negative reduced cost enters. The first two pivots will be the same as in Table 1. The candidates for the lexicographically smallest row are indicated on the right side (in appropriate detail if there is only one candidate, there is no need to scale that row just to find the...
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Hw8_Sol - Math464 HW 8 Due on Tuesday Mar 23 1 Linear...

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