minitab 9 - MINITAB Topic 9: Section 9.3, 9.4 1. Blackboard...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon
MINITAB Topic 9: Section 9.3, 9.4 1. Blackboard Lecture Notes, Slide 9: Example 1 MTB > pone 500 235; SUBC> usez; SUBC> confidence 99. Output in MINITAB 14: Test and CI for One Proportion Test of p = 0.5 vs p not = 0.5 Sample X N Sample p 99% CI Z-Value P-Value 1 235 500 0.470000 (0.412506, 0.527494) -1.34 0.180 Output in MINITAB 15: Test and CI for One Proportion Sample X N Sample p 99% CI 1 235 500 0.470000 (0.412506, 0.527494) Using the normal approximation. 2. Blackboard Lecture Notes, Slide 11: Example 2 MTB > pone c1; SUBC> usez; SUBC> confidence 90. Output in MINITAB 14: Test and CI for One Proportion: Response Test of p = 0.5 vs p not = 0.5 Event = Y Variable X N Sample p 90% CI Z-Value P-Value Response 61 100 0.610000 (0.529772, 0.690228) 2.20 0.028 Output in MINITAB 15: Test and CI for One Proportion: Response Event = Y Variable X N Sample p 90% CI Response 61 100 0.610000 (0.529772, 0.690228) Using the normal approximation.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
3. Blackboard Lecture Notes, Slide 32: Problem 1
Background image of page 2
Image of page 3
This is the end of the preview. Sign up to access the rest of the document.

This note was uploaded on 02/14/2011 for the course STAT 250 taught by Professor Sims during the Spring '08 term at George Mason.

Page1 / 3

minitab 9 - MINITAB Topic 9: Section 9.3, 9.4 1. Blackboard...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online