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Minitab 10c

# Minitab 10c - MTB> ptwo c1 c2 SUBC> pooled SUBC>...

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MINITAB Handout for Topic 10 c 1. Blackboard Lecture Notes, Slide 63: Example 1 MTB > ptwo 100 55 200 80; SUBC> pooled; SUBC> confidence 95; SUBC> alternative 0. Test and CI for Two Proportions Sample X N Sample p 1 55 100 0.550000 2 80 200 0.400000 Difference = p (1) - p (2) Estimate for difference: 0.15 95% CI for difference: (0.0311835, 0.268817) Test for difference = 0 (vs not = 0): Z = 2.46 P-Value = 0.014 2. Blackboard Lecture Notes, Slide 65: Example 2
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Unformatted text preview: MTB > ptwo c1 c2; SUBC> pooled; SUBC> confidence 90; SUBC> alternative -1. Test and CI for Two Proportions: Current, Former Event = Y Variable X N Sample p Current 73 120 0.608333 Former 86 120 0.716667 Difference = p (Current) - p (Former) Estimate for difference: -0.108333 90% upper bound for difference: -0.0306153 Test for difference = 0 (vs < 0): Z = -1.77 P-Value = 0.038...
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