HW2-11_ans - 2 O Once the solids are dissolved dilute the...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Homework #2 1. A Tris 0.9 moles of Tris x 121.4 g x 1.0 L = 109.3 g of Tris L mole Boric Acid 0.9 moles of Boric Acid x 61.84 g x 1.0 L = 55.6 g of Boric Acid L mole EDTA 20 mmoles of EDTA x 292.2 g x 1.0 L x 1 mole = 5.84 g of EDTA L mole 1000 mmoles Dissolve 109.3 g of Tris, 55.6 g of Boric Acid and 5.84 g of EDTA in about 0.5 L of H 2 O. Once dissolved, dilute the stock solution to 1.0 L with H 2 O in a graduated cylinder to form 10x TBE. B Tris 2 moles of Tris x 121.4 g x 1.0 L = 242.8 g of Tris L mole EDTA 0.5 moles of EDTA x 292.2 g x 1.0 L = 146.1 g of EDTA L mole Acetic Acid 17.4M to 2M C 1 V 1 = C 2 V 2 17.4 M x V 1 = 2 M x 1.0 L V 1 = 2 M x 1.0 L 17.4 M = 0.115 L or 115 ml of 17.4 M Acetic Acid Dissolve 242.8 g of Tris, 146.1 g of EDTA and also dilute 115 ml of concentrated acetic acid in about 0.5 L of H
Image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 2 O. Once the solids are dissolved, dilute the stock solution to 1.0 L with H 2 O in a graduated cylinder to make 50x TAE. 2. TBE-dilute 10x to 0.5x C 1 V 1 = C 2 V 2 (10x) x V 1 = (0.5x) x 1.0 L V 1 = (0.5x) x 1.0 L (10x) = 0.05 L or 50 ml of 10x TBE Dilute 50 ml of 10x TBE to 1.0 L with H 2 O in a graduated cylinder to make 0.5x TBE. (Also, you could say 50 ml of 10x TBE plus 950 ml of H 2 O.) 3. TAE-dilute 50x to 1x C 1 V 1 = C 2 V 2 (50x) x V 1 = (1x) x 500 ml V 1 = (1x) x 500 ml (50x) = 10 ml of 50x TAE Dilute 10 ml of 50x TAE to 500 ml with H 2 O in a graduated cylinder to make 1x TAE. (Also, you could say 10 ml of 50x TAE and 490 ml of H 2 O.) 4. Methionine Met M 5. Cysteine Cys C...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern