HW2-11_ans - 2 O. Once the solids are dissolved, dilute the...

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Homework #2 1. A Tris 0.9 moles of Tris x 121.4 g x 1.0 L = 109.3 g of Tris L mole Boric Acid 0.9 moles of Boric Acid x 61.84 g x 1.0 L = 55.6 g of Boric Acid L mole EDTA 20 mmoles of EDTA x 292.2 g x 1.0 L x 1 mole = 5.84 g of EDTA L mole 1000 mmoles Dissolve 109.3 g of Tris, 55.6 g of Boric Acid and 5.84 g of EDTA in about 0.5 L of H 2 O. Once dissolved, dilute the stock solution to 1.0 L with H 2 O in a graduated cylinder to form 10x TBE. B Tris 2 moles of Tris x 121.4 g x 1.0 L = 242.8 g of Tris L mole EDTA 0.5 moles of EDTA x 292.2 g x 1.0 L = 146.1 g of EDTA L mole Acetic Acid 17.4M to 2M C 1 V 1 = C 2 V 2 17.4 M x V 1 = 2 M x 1.0 L V 1 = 2 M x 1.0 L 17.4 M = 0.115 L or 115 ml of 17.4 M Acetic Acid Dissolve 242.8 g of Tris, 146.1 g of EDTA and also dilute 115 ml of concentrated acetic acid in about 0.5 L of H
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Unformatted text preview: 2 O. Once the solids are dissolved, dilute the stock solution to 1.0 L with H 2 O in a graduated cylinder to make 50x TAE. 2. TBE-dilute 10x to 0.5x C 1 V 1 = C 2 V 2 (10x) x V 1 = (0.5x) x 1.0 L V 1 = (0.5x) x 1.0 L (10x) = 0.05 L or 50 ml of 10x TBE Dilute 50 ml of 10x TBE to 1.0 L with H 2 O in a graduated cylinder to make 0.5x TBE. (Also, you could say 50 ml of 10x TBE plus 950 ml of H 2 O.) 3. TAE-dilute 50x to 1x C 1 V 1 = C 2 V 2 (50x) x V 1 = (1x) x 500 ml V 1 = (1x) x 500 ml (50x) = 10 ml of 50x TAE Dilute 10 ml of 50x TAE to 500 ml with H 2 O in a graduated cylinder to make 1x TAE. (Also, you could say 10 ml of 50x TAE and 490 ml of H 2 O.) 4. Methionine Met M 5. Cysteine Cys C...
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This note was uploaded on 02/15/2011 for the course BCHS 3304 taught by Professor Johnson during the Spring '08 term at University of Houston.

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HW2-11_ans - 2 O. Once the solids are dissolved, dilute the...

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