ch4 - F m y = (2) 88 2 9 . N kg = T a f F G g = 88 2 . N T...

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4.28 First, consider the block moving along the horizontal. The only force in the direction of movement is T . Thus, Fm x = a a a a (1) T = 5 kg a f Next consider the block that moves vertically. The forces on it are the tension T and its weight, 88.2 N. We have Fm
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Unformatted text preview: F m y = (2) 88 2 9 . N kg = T a f F G g = 88 2 . N T G T G n G FIG. P4.28 Note that both blocks must have the same magnitude of acceleration. Equations (1) and (2) can be added to give 88 2 14 . N kg = b a g . Then 4.43 4.45 4.54...
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ch4 - F m y = (2) 88 2 9 . N kg = T a f F G g = 88 2 . N T...

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