question17 - E Gv Gv A 0 3 p5 2 42 D B C 901701 9 cC ` ABCD...

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A p B C D 4 2 5 2 3 G v ±/ ² G v ³ « ³0
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901701
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c ª* ABCD C ª P 9 =39 =49 =59 C ª ABCD 9
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901702
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a 1 ,a 2 ,….,a 2001 9 2001,2002,2003,….4000,4001 = (1)(2001 - a 1 ) × (2002 - a 2 ) × (2003 - a 3 ) × ….. × (4001 - a 2001 ) (2)(1 - a 1 ) × (2 - a 2 ) × (3 - a 3 ) × ….. × (2001 - a 2001 )
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901703
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9 C á c+ 4 ª* ` · (1) ª*Љ E (2) Š [email protected] ‹E
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A C / B D // A / C // B / D A // C B // D / ° 901704 ABDC xy y d= ACC / A / 9 BDD / B / 9 =39 =3 9 ACC / A / 9 BDD / B / 9 3 d A / C / D / B / 9 A / C / C // A // 9 B / D / D // B // 9 =99 =9 A / C / C // A // 9 B / D / D // B // 9 9 = xy y ABDC 9 6558 d 9 901705 9 a 1 ,a
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