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Unformatted text preview: 2. a. = E hcÎ» the units for stress would be Joulessecmsm = Joule b. = E hcÎ» = .-/ h 6 6256x10 34Joules sec = , , / c 299 792 458 m s = .-Î» 5 9x10 6 meters = .-/ ( , , ) .- E 6 6256x10 34Joules sec 299 792 458ms 5 9x10 6 meters = 1.2x10-30 Joule c. The inputs would be h is known as Planckâ€™s constant, c for the speed of light which is 299,792,458 m/s, and for the wavelength of light in meters. The outputs would be E which Î» is the energy of the photon. The algorithm would start off with inputting Planckâ€™s constant and the speed of light and multiplying them together. Then inputting the last variable which is the wavelength of light in meters. Then taking the result of the multiplication and dividing it by the wavelength of light and outputting the result....
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- Spring '08
- Light, Speed of light, Kilogram, Metre, Gabriela Velez