FRE6083_HW1_solutions

# FRE6083_HW1_solutions - Solutions Question 1(a u1D434...

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Unformatted text preview: Solutions Question 1 (a) u1D434 u1D450 = { u1D465 < 1 ∪ u1D465 > 5 } (b) u1D434 ∪ u1D435 = { 1 ≤ u1D465 ≤ 5 } ∪ { 3 < u1D465 ≤ 7 } = { 1 ≤ u1D465 ≤ 7 } (c) u1D435u1D436 u1D450 = { 3 < u1D465 ≤ 7 } ∩ { u1D465 > } = u1D435 (d) u1D434 u1D450 u1D435 u1D450 u1D436 u1D450 = { ( u1D434u1D448u1D435 ) u1D450 u1D436 u1D450 = { u1D465 < 1 ∪ u1D465 > 7 } ∩ { u1D465 > } = { < u1D465 < 1 ∪ u1D465 > 7 } (e) ( u1D434 ∪ u1D435 ) u1D436 = { 1 ≤ u1D465 ≤ 7 } ∩ { u1D465 ≤ } = u1D719 Question 2 Given u1D435 u1D45B = ∞ uni222A.alt02 u1D456 = u1D45B u1D434 u1D456 and u1D435 u1D45B +1 = ∞ uni222A.alt02 u1D456 = u1D45B +1 u1D434 u1D456 then u1D435 u1D45B = u1D435 u1D45B +1 ∪ u1D434 u1D45B ⊃ u1D435 u1D45B +1 Similarly, given u1D436 u1D45B = ∞ uni2229.alt02 u1D456 = u1D45B u1D434 u1D456 and u1D436 u1D45B +1 = ∞ uni2229.alt02 u1D456 = u1D45B +1 u1D434 u1D456 then u1D436 u1D45B = u1D434 u1D45B ∩ u1D436 u1D45B +1 ⊂ u1D436 u1D45B +1 Question 3 u1D446 = { ( u1D44F 1...
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## This note was uploaded on 02/16/2011 for the course FE 6083 taught by Professor Neveskyi during the Spring '11 term at NYU Poly.

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FRE6083_HW1_solutions - Solutions Question 1(a u1D434...

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