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Unformatted text preview: Proof 3: 1. Assume a  b . This means that b/a = k for some integer k . This also means that ak = b . This means we can also say that b is divisible by a . 2. Since b is divisible by a , any multiple of b is divisible by a . Therefore, bc is divisible by a . This is what we had to prove. 1 Proof 4: 1. Since a  b is dened, we can say ak = b for some integer k . 2. Multiply both sides to obtain akc = bc . 3. This shows that a  bc and a  b . 2...
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This note was uploaded on 02/16/2011 for the course MA 315 taught by Professor Peterturbek during the Spring '11 term at Purdue University Calumet.
 Spring '11
 PeterTurbek
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