Digital Logic HW 2 Solutions

# Digital Logic HW 2 Solutions - Solution. Problem 1 2.25....

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Solution. Problem 1 2.25. The simplest SOP expression for the function is f = x1’x3’x5’ + x1’x3’x4’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’x5’ + x1’x3’x4’ + x1’x4x5 + x1’x3’x5 + x1x2’x3’x5 = x1’x3’x5’ + x1’x3’x5 + x1’x3’x4’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x3’x4’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x3’x4’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x2’x3’x5 + x1’x4x5 + x1x2’x3’x5 = x1’x3’ + x1’x4x5 + x1’x2’x3’x5 + x1x2’x3’x5 = x1’x3’ + x1’x4x5 + x2’x3’x5 Problem 2 2.26. The simplest POS expression for the function is f = (x1’ + x3’ + x4’)(x2’ + x3’ + x4)(x1 + x2’ + x3’) = (x1’ + x3’ + x4’)(x2’ + x3’ + x4)(x1’ + x2’ + x3’)(x1 + x2’ + x3’) = (x1’ + x3’ + x4’)(x2’ + x3’ + x4)(x2’ + x3’) = (x1’ + x3’ + x4’)(x2’ + x3’)

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## This note was uploaded on 02/16/2011 for the course EE 4745 taught by Professor Rai during the Spring '07 term at LSU.

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Digital Logic HW 2 Solutions - Solution. Problem 1 2.25....

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