Lecture17

Lecture17 - ik kx dx ik kx kx i i i ik i kx kx = + = -+ =-+...

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We can also differentiate exp( ikx ) as if the argument were real. [ ] [ ] exp( ) exp( ) cos( ) sin( ) sin( ) cos( ) 1 sin( ) cos( ) 1/ sin( ) cos( ) d ikx ik ikx dx d kx i kx k kx
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Unformatted text preview: ik kx dx ik kx kx i i i ik i kx kx = + = -+ =-+ -= = + Proof : But , so :...
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This note was uploaded on 02/16/2011 for the course PHYS 2163 taught by Professor Briscoe during the Fall '10 term at GWU.

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