question-sbptrial-P2-07 - SULIT 1449/2 Matematik Kertas 2...

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SEKTOR SEKOLAH BERASRAMA PENUH BAHAGIAN SEKOLAH KEMENTERIAN PELAJARAN MALAYSIA PEPERIKSAAN PERCUBAAN SELARAS SBP SIJIL PELAJARAN MALAYSIA 2007 MATEMATIK Kertas 2 Dua jam tiga puluh minit Pemeriksa Bahagian Soalan Markah Penuh Markah Diperoleh A 1 4 2 4 JANGAN BUKA KERTAS SOALAN INI SEHINGGA DIBERITAHU 1. Kertas soalan ini mengandungi dua bahagian : Bahagian A dan Bahagian B . Jawab semua soalan daripada Bahagian A dan empat soalan dalam Bahagian B . 2.Jawapan hendaklah ditulis dengan jelas dalam ruang yang disediakan dalam kertas soalan. Tunjukkan langkah-langkah penting. Ini boleh membantu anda untuk mendapatkan markah. 3.Rajah yang mengiringi soalan tidak dilukis mengikut skala kecuali dinyatakan. 4.Satu senarai rumus disediakan di halaman . 5.Anda dibenarkan menggunakan kalkulator saintifik yang tidak boleh diprogram. 3 3 4 4 5 5 6 4 7 6 8 5 9 5 10 6 11 6 B 12 12 13 12 14 12 15 12 16 12 Jumlah Kertas soalan ini mengandungi 26 halaman bercetak. SULIT 1449/2 Matematik Kertas 2 Ogos 2007 2 1 2 jam 1449/2 1449/2 2007 Hak Cipta Sektor SBP [Lihat sebelah SULIT NAMA : TINGKATAN :
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Untuk Kegunaan Pemeriksa SULIT 1449/2 MATHEMATICAL FORMULAE The following formulae may be helpful in answering the questions. The symbols given are the ones commonly used. RELATIONS 1 a m x a n = a m+ n 2 a m ÷ a n = a m – n 3 ( a m ) n = a mn 4 A -1 = bc ad - 1 - - a c b d 5 P ( A ) = ) ( ) ( S n A n 6 P ( A ) = 1 - P(A) 7 Distance = 2 2 1 2 1 2 ( ) ( ) x x y y - + - 8 Midpoint, ( x, y ) = + + 2 , 2 2 1 2 1 y y x x 9 Average speed = 10 Mean = 11 Mean = 12 Pythagoras Theorem c 2 = a 2 + b 2 13 m = 1 2 1 2 x x y y - - 14 -intercept -intercept y m x = - SHAPES AND SPACE 1449/2 SULIT 2 distance travelled time taken sum of data number of data sum of (class mark × frequency) sum of frequencies
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Untuk Kegunaan Pemeriksa SULIT 1449/2 1 Area of trapezium = 2 1 × sum of parallel sides × height 2 Circumference of circle = π d = 2 π r 3 Area of circle = π r 2 4 Curved surface area of cylinder = 2 π rh 5 Surface area of sphere = 4 π r 2 6 Volume of right prism = cross sectional area × length 7 Volume of cylinder = π r 2 h 8 Volume of cone = 3 1 π r 2 h 9 Volume of sphere = 3 4 π r 3 10 Volume of right pyramid = 3 1 × base area× height 11 Sum of interior angles of a polygon = ( n – 2) × 180˚ 12 arc length angle subtended at centre circumference of circle 360 = o 13 area of sector angle subtended at centre area of circle 360 = o 14 Scale factor , k = PA PA ' 15 Area of image = k 2 × area of object Section A [52 marks ] Answer all questions in this section. 1449/2 [Lihat sebelah SULIT 3
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Untuk Kegunaan Pemeriksa SULIT 1449/2 1 Solve the quadratic equation 3 5 4 2 2 x x - = - . [4 marks ] Answer : 2 Calculate the value of x and y that satisfy the following simultaneous linear equations: 1449/2 SULIT 4
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Kegunaan Pemeriksa SULIT 1449/2 5 2 1 8 3 5 = + - = - y x y x [4 marks ] Answer : 3 On the graph in the answer space, shade the region which satisfies the three inequalities 2 y x – 4, y 2 x + 1 and y < 1. 1449/2
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question-sbptrial-P2-07 - SULIT 1449/2 Matematik Kertas 2...

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