scheme- sbp trial -P2

scheme- sbp trial -P2 - SULIT 1449/2 Matematik Kertas2...

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SULIT 1449/2 1449/2 Matematik Kertas2 Peraturan Pemarkahan Ogos 2007 SEKTOR SEKOLAH BERASRAMA PENUH BAHAGIAN SEKOLAH KEMENTERIAN PELAJARAN MALAYSIA PEPERIKSAAN PERCUBAAN SIJIL PELAJARAN MALAYSIA 2007 MATEMATIK Kertas 2 PERATURAN PEMARKAHAN Peraturan pemarkahan ini mengandungi 12 halaman. [Lihat sebelah 1449/2 SULIT Jumlah Markah = 1 2 100% 140 Kertas Kertas + ×

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Section A [ 52 marks ] No Marking Scheme Marks 1 8x 2 – 14x + 3 = 0 ( 4x – 1 ) ( 2x – 3 ) = 0 x = 1 4 or x = 3 2 K1 K1 N1 N1 4 2 5x + 2 5 y = 25 2 11 y = 33 y = 6 x = 2 P1 K1 N1 N1 4 3 y = 1 2 y = x - 4 y = 2 x + 1 O y Draw the straight line y = 1 Region shaded correctly Notes : 1. Region that satisfies any two inequalities : P1 2. Deduct 1 mark from K1P2 if the straight line y = 1 drawn in solid line K1 P2 3 2
Marking Scheme Marks 4 Identify JSM or MSJ or angle marked on the diagram correctly tan JSM = 12 8 or equivalent 56 3 o or 56 o 19 P1 K2 N1 4 5 (a) (b) y = 3 Gradient of JK = 1 2 or the gradient being used ( 29 1 2 3 2 c - = - + or ( 29 ( 29 2 1 3 2 y x - - = - - 1 1 2 2 y x = + or equivalent y - intercept = 1 2 P1 P1 K1 N1 P1 5 6 1 6 7 8 3 × × × 1 22 7 7 6 2 7 2 2 × × × 1 6 7 8 3 × × × + 1 22 7 7 6 2 7 2 2 × × × 227.5 K1 K1 K1 N1 4 7(a) (b) 5 . 3 7 22 2 360 60 × × × or 7 7 22 2 360 180 × × × 7 + 3.5 + 3.5 +22 + 11 3 2 39 3 or 39.67 2 7 7 22 360 180 × × or 2 7 7 22 360 60 × × or 2 5 . 3 7 22 360 180 × × or 2 5 . 3 7 22 360 60 × × 2 7 7 22 360 180 × × -

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This note was uploaded on 02/16/2011 for the course FIN 355 taught by Professor Tang during the Spring '10 term at Aachen University of Applied Sciences.

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scheme- sbp trial -P2 - SULIT 1449/2 Matematik Kertas2...

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