{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Math111i_GroupQuiz1_Solutions

Math111i_GroupQuiz1_Solutions - -1 = 2-4-1-2 =-2 m-1 0...

Info icon This preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Math 111I Sec 001 Group Quiz 1 Name Directions: Read each question carefully and answer in the space pro- vided. The use of calculators is allowed, but not necessary. There are 10 points possible. To receive partial credit on any problem work must be shown. 1. Consider the following table with x and y . x y -2 4 -1 2 0 -5 1 3 2 0 3 1 a. (5 points) Calculate the average rate of change between every two x values given in the table. That is calculate m [ a,a +1] for every a = - 2 , - 1 , . . . , 3. b. (5 points) Find the average rate of change between x = - 2 and x = 3. Does this average rate of change describe the function better than those computed in part a.? Solutions. a. We simply compute the following average rates of change
Image of page 1

Info icon This preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: -1] = 2-4-1-(-2) =-2 m [-1 , 0] =-5-2-(-1) =-7 m [0 , 1] = 3-(-5) 1-= 8 m [1 , 2] =-3 2-1 =-3 m [2 , 3] = 1-3-2 = 1 . Math 111I Sec 001 Group Quiz 1 b. Next we find the average rate of change between x =-2 and x = 3, which follows as m [-2 , 3] = 1-4 3-(-2) =-3 5 . We gain a better understanding of the function from the values in a. because we get to see how the function is changing more often, and from those values if we take the average of (-2 ,-7 , 8 ,-3 , 1) we obtain-3 / 5. So because we can find the answer to b. from a., then we can say that a. tells us more about the function....
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern