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Unformatted text preview: 4 / 54 b2(6 / 5) . Now we make this computation on the side.4 54 =4 55 5 Â· 4 =4 520 5 =24 52Â±6 5 Â² =2 + 6 5 = 6 55 5 Â· 2 = 6 510 5 =4 5 . Thus we have that Â± a 2 / 5 b a2 b 3 / 5 Â²2 = a4 / 54 b2(6 / 5) = a24 / 5 b4 / 5 = 1 a 24 / 5 b 4 / 5 . 4. (2 points) Given that there are 5280 feet in 1 mile (ask if any other conversion factors are needed), convert 30 in/sec to mi/day. Math 111I Sec 001 Quiz 5 Solutions. Our computation follows as 30in 1sec Â· 1ft 12in Â· 1mi 5280ft Â· 60sec 1min Â· 60min 1hr Â· 24hrs 1day = 30 Â· 60 Â· 60 Â· 24 mi 12 Â· 5280 days = 2 , 592 , 000 63 , 360 mi / day = 40 . 91 mi / day...
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This note was uploaded on 02/16/2011 for the course MATH 111 taught by Professor Hitchcock during the Fall '08 term at South Carolina.
 Fall '08
 HITCHCOCK
 Math

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