SCAN0059 - relationship Since we do not know x0 we will...

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Unformatted text preview: .\ /, relationship. Since we do not know x0, we will slightly rearrange the equation to: .. 1 ln(x) = K 7+ ln(xa) .5- Thus, using a plot we can obtain a number for K" and for xo by plotting ln(x) as our y and 1/2 as ourx: Question 4 o r .. —. -2 0.00005 0.0001 0.00015 0.0002 0.00025 -12 44 ‘6: y=-64189x<1.4349 “i 1/e2 The equation is 1n(x)= -641i39*]/aZ -1i4349 Put in our given a: )(czizsmrx b) If adjusted, what is the new mole fraction? Using the same format as before, but now we are given the slope and intercept values, just substitute them in: X=,006 c) Explain your results When LiCl was added, the mole fraction increased substantially, Adding THIS salt to water resulted in setting in. Note that different salts have different effects: some salts do the opposite (salt out). While the effects of different salts are qualitatively understood (the Hofrneister series), the quantitative and physical explanations are still under development, 5. Solvent flux with concentration polarization (graduate students only: 5 pts) a) Solve the steady»state mass balance Consulting a transport phenomena textbook, one finds the steady state mass balance to be: 2 Vin-fl = D: d Cf dz dz' and the boundary conditions: F0, CZFCO z=-6, C8:CS Integrating the mass balance twice, we obtain: Ca : CI Eexp‘h + C2 C1 = Cn—ECI, where C. is given above W b) Relate the velocity to the other variables - The hint we are given provides an expression for dc/dz evaluated at 2:0. In part a, we obtained a separate expression for dc/dz (on our way to solving for Ca): —* c —c gm exp.” ,whm C. 7—HT 2 —{(l—exp ”‘ VT” If we evaluate this at 2:0. we get: dCa _ vm / Ds * (C0 — Cs) at fl; 2 l—exp 0“ ...
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