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Sample Test 1 (lightbulb case) calcs

Sample Test 1 (lightbulb case) calcs - A data Brand 1 2 3 4...

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773a562d55eb00ba1914a230cd4790b52102b410.xls Brand A data Brand A lifetime (hr) LL UL freq rel freq 684 600 700 1 0.05 720 700 800 2 0.10 773 800 900 5 0.25 831 900 1000 8 0.40 852 1000 1100 4 0.20 859 1100 1200 0 0.00 870 20 1.00 893 909 922 926 939 943 954 972 997 1005 1016 1052 1080 700 800 900 1000 1100 1200 0.00 0.10 0.20 0.30 0.40 0.50 Lifetime (hours) Relative Frequency A B C D E F G H I 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23
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Brand A lifetime (hr) bins lifetime (hr) dev dev^2 684 = min 684 -225.850 51008.2225 720 600 720 -189.850 36043.0225 773 700 773 -136.850 18727.9225 831 800 831 -78.850 6217.3225 852 855.50 900 852 -57.850 3346.6225 859 = Q1 1000 859 -50.850 2585.7225 870 870 -39.850 1588.0225 893 893 -16.850 283.9225 909 909 -0.850 0.7225 922 924.00 922 12.150 147.6225 926 = median 926 16.150 260.8225 939 939 29.150 849.7225 943 943 33.150 1098.9225 954 954 44.150 1949.2225 972 984.50 972 62.150 3862.6225 997 = Q3 997 87.150 7595.1225 1005 1005 95.150 9053.5225 1016 1016 106.150 11267.8225 1052 1052 142.150 20206.6225 1080 = max 1080 170.150 28951.0225 size n 20 sums = 0.0000 205044.5500 sum 18197 s^2 = 10791.8184 mean 909.850 s = 103.8837 median 924.000 mean < median, so left skewed max 1080.00 min 684.00 range, R 396.00 midrange 882.00 variance s^2 10791.818 st. dev., s 103.884 3s 311.651 mean + 3s 1221.501 > max, so no outliers mean - 3s 598.199 < min, so no outliers CV 0.1142 > 0.05, so the mean is not a good representation Q1 855.50 857.25 by Excel Q3 984.50 978.25 by Excel midquartile 920.00 IQR 129.00 IQR/R 0.326 < 0.5, so tightly clustered peak MoE 46.458 956.308 = xbar + MoE 863.392 = xbar - MoE # bulbs/year 9.6 UL on μ LL on μ A B C D E F G H I 1 2 3 4 5 6 7 8 9 10 11 12 13 14 15 16 17 18 19 20 21 22 23 24 25 26 27
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