Lemuel physics 2 6 - Wong, Lemuel Homework 6 Due: Mar 2...

Info iconThis preview shows pages 1–3. Sign up to view the full content.

View Full Document Right Arrow Icon

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full DocumentRight Arrow Icon
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: Wong, Lemuel Homework 6 Due: Mar 2 2007, 11:00 pm Inst: Matt Mackie 1 This print-out should have 16 questions. Multiple-choice questions may continue on the next column or page find all choices before answering. The due time is Central time. NOTE: HW is due 11pm central time, which is midnight our time. 001 (part 1 of 1) 10 points Two alpha particles (helium nuclei), each con- sisting of two protons and two neutrons, have an electrical potential energy of 6 10- 19 J . Given: k e = 8 . 98755 10 9 Nm 2 / C 2 , q p = 1 . 6021 10- 19 C , and g = 9 . 8 m / s 2 . What is the distance between these parti- cles at this time? Correct answer: 1 . 5379 10- 9 m. Explanation: Let: U electric = 6 10- 19 J , k e = 8 . 98755 10 9 Nm 2 / C 2 , q p = 1 . 6021 10- 19 C , q = 2 q p = 3 . 2042 10- 19 C , and q n = 0 C . q 1 = q 2 = 2 q p + 2 q n = 2(1 . 6021 10- 19 C) + 2(0 C) = 3 . 2042 10- 19 C U electric = k e q 1 q 2 r r = k e q 1 q 2 U electric = k e q 2 1 U electric = (8 . 99 10 9 N m 2 / C 2 ) (3 . 2042 10- 19 C) 2 6 10- 19 J = 1 . 5379 10- 9 m . keywords: 002 (part 1 of 2) 10 points An electric field does 11 J of work on a . 0009 C charge. What is the voltage change? Correct answer: 12222 . 2 V. Explanation: Let : W = 11 J and q = 0 . 0009 C . Work is W = qV V = W q = 11 J . 0009 C = 12222 . 2 V . 003 (part 2 of 2) 10 points The same electric field does 22 J of work on a . 0018 C charge. What is the voltage change? Correct answer: 12222 . 2 V. Explanation: Let : W = 22 J and q = 0 . 0018 C . The voltage change is V = W q = 22 J . 0018 C = 12222 . 2 V . keywords: 004 (part 1 of 1) 10 points Two insulating spheres having radii 0 . 12 cm and 0 . 32 cm, masses 0 . 11 kg and 0 . 41 kg, and charges- 4 C and 2 C are released from rest when their centers are separated by 1 . 2 m . How fast is the smaller sphere moving when they collide? Correct answer: 15 . 2795 m / s. Explanation: Wong, Lemuel Homework 6 Due: Mar 2 2007, 11:00 pm Inst: Matt Mackie 2 Let : k e = 8 . 99 10 9 N m 2 / C 2 , r 1 = 0 . 12 cm = 0 . 0012 m , r 2 = 0 . 32 cm = 0 . 0032 m , m 1 = 0 . 11 kg , m 2 = 0 . 41 kg , q 1 =- 4 C =- 4 10- 6 C , q 2 = 2 C = 2 10- 6 C , and d = 1 . 2 m . By conservation of momentum 0 = m 1 v 1- m 2 v 2 v 2 = m 1 v 1 m 2 By conservation of energy ( K + U ) i = ( K + U ) f 0 + k e q 1 q 2 d = 1 2 m 1 v 2 1 + 1 2 m 2 v 2 2 + k e q 1 q 2 r 1 + r 2 k e q 1 q 2 d = 1 2 m 1 v 2 1 + 1 2 m 2 m 1 v 1 m 2 2 + k e q 1 q 2 r 1 + r 2- k e q 1 q 2 1 r 1 + r 2- 1 d = m 1 v 2 1 2 m 2 ( m 1 + m 2 ) ....
View Full Document

Page1 / 7

Lemuel physics 2 6 - Wong, Lemuel Homework 6 Due: Mar 2...

This preview shows document pages 1 - 3. Sign up to view the full document.

View Full Document Right Arrow Icon
Ask a homework question - tutors are online