Quiz1B - ME 205 STATICS FALL 2010 SECTION 4 QUIZ 1 SURNAME...

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Unformatted text preview: ME 205 STATICS FALL 2010 SECTION 4 QUIZ 1 SURNAME, Name: SOLUTION Student ID: A bolt 0n the steel platform is to be tightened by means of a socket wrench. Determine the moment MOB produced by the force F which tends to rotate the bolt about the OB axis. (Note that the force F is parallel to the xz—plane.) F2100 N 2120.05 m b=0.25 m (1)330” B=60° Smog force A? is parallel ’lD X-Z- Jam, [4' has no&— Wri+e T3 m vedor mlafioo, 3: Ex "('31 --> ‘ A F=-Fsm¢ T,— Fensfil’. .6 F=—|OO $0307, — IOU cos 30E -—5 h J? “ F=-|OO(O.S)L-|OO(T>|¢ Bram- 513th [NJ —-5 Poslfion vec+vr r '15 directed from midpoint on the 06am h) and point on file line 0{ action 0{+he force E. In this flutes—Hon 33A is used, kul’ GHQ/FM‘I‘NGJKB FEM can he, used alSo. WriJre, ?[=?OA) m vadvr nfiaiion, A A =13x+rJ+ F; =a1+bcogej +bsin92 = o. 05 t + 0.25 (105 503 + 0,255m 60 {2 r: 0.051: +025 (0,533 +0.25 (J?) 2 ?= 0.051: + 0.1.25; + o. QEEE [M] W momenJo MOE, of force {‘5’ atom +m axis 03 can be, “found lg, M03 '-‘ (:4- (?KE) w hare Jv-Nr-Nx'fi A I LL: W’qu VEdUI' 61.50% 08 axis (FAKE): Mon/lard; of {—3) abowt Poi/rt O (or abw+ FORM: 3) .CoJCulaaLe; EL. —) _) -5 M0 = r x F M: = (0,052+ 0.126] +O,I25\I§' E) x (~50: - 50W E) 542 = 50(0. 05M?“ + gowns) E ~50(0. IQEN’EVL — 50(0. :QSNETJ fi[email protected]—3.754E*+6.1512 [Mm] 1+ is ‘h‘ixfkfl Mod aJOer OE: ands, :1: ”L Calculcufta M03) M03 = 0- E30 M03: ’3 - (—6.264371: — 375$? 6.515%.) Mug ... — 6.15687 Mag-4* 10.83 [Mm] 159, care, 1 +14an (AmL prodchr Pmoluces a scalar resLJLh‘- The V6 rQSuH iMimies fined" 7%; Sense of M03 is in H42, 0P osi’ra direcfion as u. wri+e flag, in \IemLDr moirafion, HOB: M08 [1 .4, Mow—v0.23; [Mm] We scalar filpm 9&3ch Can also be wn‘Hen as, f, o o I 0 O Mova'fix {3) t rx r5 r1? = 0.05 (1:25 0.125431 Fx 0 “F.3- “50 0 “50¢? Lewd: wiH 12;;de same, Fesufkfie careful Hard ‘H/u's prodm also produces scalar resuH. MOB: l [D.l26(*50~[31)~ o(o.z25\13‘)] Mog=—e.25\r§' [Mm] ...
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