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chap 13 test

# chap 13 test - l A 2-kg mass rests on a ﬂat horizontal...

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Unformatted text preview: l. A 2-kg mass rests on a ﬂat horizontal bar when the bar begins to rotate in the vertical plane about 0 with a constant angular acceleration 06 = l rad lsecz. The mass is observed to slip relative to the bar when the bar is at 30" above the horizontal. Determine a) the static coefficient of friction between the mass and the bar, and b) the direction of the mass when it slips (toward or away from O). .. 2/9.g:)(.5 ) + 2/2)(} a???) —- ”771M to ._ 0,,31 2.09 n - 75warJ ‘M .m H 1. A l—lb block shown is given an initial velocity V0 = 14 ft/sec to the right when 9 = 0°, causing it to slide up the smooth circular surface. Determine the magni- tude of the velocity When 6 = 60°. . 2. +\E‘E\ = Ns Midas = "4% /SF .7. --ma\$rh9 3 M41 :3 Mr“ -E “aw-9 = W = 3% : 2. . _ Va. 6 f N = mﬁwsa +.m_1{ 2’ Mmc°59+ RF] -‘ nk‘ /«: r /\ _. ' i: if 019 :L . a}! 9': y" %\N . 0P: 9 49 g}, 9&8 . ‘V‘ a ma (-(Ap‘SMQ 019' " {ValV v so ’2. V «~st 1 ... ( a . (9 "1 Iﬁ‘ 2. The two blocks shown are connected by‘ a cable and start from rest. BlockA slides on a smooth surface. Assume that the pulley is frictiOnless with negligibile mass. ' ' Determine: a) acceleration of each block, A and B, b) tension in the cable, . c) distance. block A slides after 2 seconds. “30091.8! ) §_ x 2. A 250- kg cart shown is traveling to the right with a speed of 7 m/sec when it comes to an inclined plane. Determine a) the acceleration of the cart during its travel up the inclined plane, and b) the distance d that the cart will travel up the inclined plane before coming to a rest. 3. ; The altitude Of a satellite in an elliptical orbit around the earth is 25,000 miles at the apogee and 3,000 miles at the perigee position. When the satellite is at the angle 0 = 1200 , determine a) the radial distance r from the center of the earth, and b) the velocity v of the satellite at this position. y ‘0, 3 3960+ 3:309 :2 6940 no; (a = SQéo + 25000 2* 28360159 ‘ —-—‘ = 69600—60 : 28143600 “6) 641: e: 0.6l2 V;- %({+c) VP2'2‘F-I‘Zg‘é ‘P/w Ry 92:20 _ Mm V 3 6—? ieL+2€w5(Zo'+l ‘~‘-‘ ’3)?“ ‘94—: 3. I ' _ v z: j. _____L_...——-—~ :- 161/65" .mﬂcs 6% (1+? 605 I753 . - 3. The altitude (distance above the surface of the earth) of a satellite at apogee is 21,000 miles. the altitude at perigee is 2500 miles. ' Determine a) the eccentricity e of the orbit b) the velocities at perigee, VP, and at apogee, V A c) the position of the satellite r and the velocity when 0 = 150° N 21' 3960' + 2936 (3)460 T? Q: 3%0 4- 210m: 3 255940 is I I 745’éo(/-€3 e 2 .SS‘) = \$490 [(+6) 2 Gm _ 7 . 2%. 2'- 6 - ('31;qu ”3 at, at?“ ({+.;’8:?} VP __ Aﬂ+€§ 2:, 7 (a) 0: 0 V} {Mata )(52 so) VP 3 25,500 4%“ l 2: Lie 3 4650‘? Fair 8: 151)" ‘h?’ I 5 . «p = __———~ .___.._—-—-—--——-"‘ 2 - Ito—5 Kto H or 20300 rm!“ GM; !-+ 6: 905150 —-——--\ 81+ 2€Cos [50. + l .1" Q, 220 41/52:. GM 7. l ...
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