{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Page 10 - 13 The graphof an electric field in one...

Info icon This preview shows page 1. Sign up to view the full content.

View Full Document Right Arrow Icon
Image of page 1
This is the end of the preview. Sign up to access the rest of the document.

Unformatted text preview: 13.) The graphof an electric field in one dimension is shown to the right. What would the corresponding electrical potential graph look like? figlntign: The electrical potential difference between any two points is the area under the electric field versus position graph (AV: E-dr). Assuming the electrical potential is some positive value, it will get bigger between zero and a, will get still bigger but not as fast between a and 2a, will not change at all between 2:; and 3a, then will get bigger again, etc. The graph is shown to the right. 14.) The graph of an electrical potential field in one dimension is shown to the right. What would the corresponding electric field graph look like? Solution: The slope of the electrical potential function at any point is equal to the electric field function (E = -dV/dx). That slope is constant and negative in the section from zero to 2:1, then is zero, then constant and positive from 3a to 4a., then varies from positive to zero to negative in a relatively linear way. The graph is shown to the right. 15.) A charge q in a constant electric field sits at a point where the electrical potential is V1, where V1 is positive. It accelerates from rest to a position at which the electrical potential is 2V1. At that point, the particle's velocity is v. a.) Is the charge positive or negative? Shim: The charge is negative. How so? It accelerates from a lower potential (i.e. V ) to higher potential (i.e. 2V ). Negative charges do that—-positive 1 1 charges accelerate from higher to lower electrical potentials. b.) If (1 had gone to a position where the electrical potential was 3V1, how fast would it have been going (do this in terms of the known velocity v)? §glutionz This is a conservation of energy problem. In the original problem, the electrical potential difference was 2V1 - VI = V]. That means the work done was W = -AV = -(vq)V . Also, given that the initial velocity was zero, the kinetic I l g____fl4 ...
View Full Document

{[ snackBarMessage ]}

What students are saying

  • Left Quote Icon

    As a current student on this bumpy collegiate pathway, I stumbled upon Course Hero, where I can find study resources for nearly all my courses, get online help from tutors 24/7, and even share my old projects, papers, and lecture notes with other students.

    Student Picture

    Kiran Temple University Fox School of Business ‘17, Course Hero Intern

  • Left Quote Icon

    I cannot even describe how much Course Hero helped me this summer. It’s truly become something I can always rely on and help me. In the end, I was not only able to survive summer classes, but I was able to thrive thanks to Course Hero.

    Student Picture

    Dana University of Pennsylvania ‘17, Course Hero Intern

  • Left Quote Icon

    The ability to access any university’s resources through Course Hero proved invaluable in my case. I was behind on Tulane coursework and actually used UCLA’s materials to help me move forward and get everything together on time.

    Student Picture

    Jill Tulane University ‘16, Course Hero Intern