CHAPTER37Atoms1*∙As n increases, does the spacing of adjacent energy levels increase or decrease?The spacing decreases.2∙The energy of the ground state of doubly ionized lithium (Z= 3) is ______ ,where E0= 13.6 eV.(a)–9E0, (b) –3E0, (c)–E0/3,(d)–E0/9.(a)3∙Bohr’s quantum condition on electron orbits requires(a)that the angular momentum of the electron about the hydrogen nucleus equal nh_.(b) that no more than one electron occupy a given stationary state.(c) that the electrons spiral into the nucleus while radiating electromagnetic waves.(d) that the energies of an electron in a hydrogen atom be equal to nE0, where E0is a constant energy and nis an integer.(e) none of the above.(a)4∙∙If an electron moves to a larger orbit, does its total energy increase or decrease? Does its kinetic energy increase or decrease? Its total energy increases; its kinetic energy decreases.5*∙∙The kinetic energy of the electron in the ground state of hydrogen is 13.6 eV = E0. The kinetic energy ofthe electron in the state n= 2 is _____.(a) 4E0,(b) 2E0, (c)E0/2,(d) E0/4.(d)6∙The radius of the n= 1 orbit in the hydrogen atom is a0= 0.053 nm. What is the radius of the n= 5 orbit?(a) 5a0, (b) 25a0, (c) a0, (d) (1/5)a0, (e) (1/25)a0.(b)7∙Use the known values of the constants in Equation 37-11 to show that a0is approximately 0.0529 nm.Evaluate Equ. 37-12, a0= h_2/mke2a0= m)10(1.6108.99109.11)10(1.05219931234−−−××××××= 5.26×10–11m = 0.0526 nm8∙The longest wavelength of the Lyman series was calculated in Example 37-2. Find the wavelengths for the transitions (a) n1= 3 to n2= 1 and (b) n1= 4 to n2= 1.
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