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Unformatted text preview: Exp. [XY] [Z2] Initial Rate 1 0.1 0.1 2.0x105 2 0.2 0.1 4.0x105 3 0.2 0.2 1.6x105 4 1.2 0.8 ? What is the Rate law of this Reaction? A. k[XY] [Z2] C. k[XY]2[Z2 D. k[XY] [Z2]2 B. k[XY]2[Z2 ] 2/21/11 Exp. [XY] [Z2] Initial rate 1 0.1 0.1 2.0x105 2 0.2 0.1 4.0x105 3 0.2 0.2 1.6x105 4 1.2 0.8 ? From exp 1 and 2, [XY] is doubled / rate is doubled(2 1 ). Rate = k[XY]a[Z2]b a = 1 From exp 2 and 3, [Z2] is doubled / rate is quadrupled (2 2 ). b = 2 Rate = k[XY]1[Z2]2 2/21/11 Exp. [XY] [Z2] Initial rate 1 0.1 0.1 2.0x105 4 1.2 0.8 ? Find rate of reaction in exp. 4 Rate = k[XY] [Z2]2 1. Find k from exp.1 ; 2.0x105 = k(0.1)(0.1)2 k = 0.02 2. Substitute k in exp.4 ; rate = 0.02(1.2)(0.8)2 = 1.536x102 2/21/11 (C17H35)3COOC3H5 + 3NaOH K 3C17H35COONa + C3H8O3 (I) This reaction is called saponification. (I) It is used to making soap. (I) The product is sodium stearate....
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 Spring '11
 John
 Chemistry, Atom, pH

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