CONTROLS LAB 1 MATLAB

CONTROLS LAB 1 MATLAB - PROBELM #1 DONE...CHECK FILE AT...

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Unformatted text preview: PROBELM #1 DONE...CHECK FILE AT SCHOOL PROBLEM #2 a) >> numf=[1 0 3] numf = 1 0 3 >> denf=[1 -4 -9 36] denf = 1 -4 -9 36 >> [K,p,k]=residue(numf,denf) K = 2.7143 -2.0000 0.2857 p = 4.0000 3.0000 -3.0000 k = EXPLAINATION The K values are called the residues and they form the contants in the numerator. The "p" values are the roots of the denominator or the poles. From the matlab response the partial expansion can be written as: b) >> numg=[1 0 -16] numg = 1 0 -16 >> deng=[1 -3 3 -1 0 0] deng = 1 -3 3 -1 0 0 >> [K,p,k]=residue(numg,deng) K = -48.0000 32.0000 -15.0000 48.0000 16.0000 p = 1.0000 1.0000 1.0000 0 0 k = EXPLAINATION The K values are called the residues and they form the contants in the numerator. The "p" values are the roots of the denominator or the poles. From the matlab response the partial expansion can be written as: PROBLEM # 4 DONE...CHECK FILE AT SCHOOL PROBLEM #5 NOT DONE!!!!!!!!!!!!!!! PROBLEM #6 NOT DONE!!!!!!!!!!!!!!! PROBLEM #7 NOT DONE!!!!!!!!!!!!!!! ...
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CONTROLS LAB 1 MATLAB - PROBELM #1 DONE...CHECK FILE AT...

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