# CW2 - boland (kbb544) – CW2 – Mackie – (10611) This...

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Unformatted text preview: boland (kbb544) – CW2 – Mackie – (10611) This print-out should have 2 questions. Multiple-choice questions may continue on the next column or page – ﬁnd all choices before answering. 001 (part 1 of 2) 10.0 points A Cessna aircraft has a lift-oﬀ speed of 125 km/h. What minimum constant acceleration does this require if the aircraft is to be airborne after a take-oﬀ run of 214 m? Correct answer: 2.8169 m/s2 . Explanation: Let : vi = 0 km/h , v = 125 km/h , x = 214 m . 1 and Under constant acceleration, 2 2 vf = vi + 2 a x = 2 a x a= 2 vf 2 2x (125 km/h)2 1000 m = 2(214 m) 1 km = 2.8169 m/s2 . 1h 3600 s 2 002 (part 2 of 2) 10.0 points How long does it take the aircraft to become airborne? Correct answer: 12.3264 s. Explanation: Under constant acceleration, vf = vi + a t = a t vf t= a 125 km/h 1000 m = 2.8169 m/s2 1 km = 12.3264 s . 1h 3600 s ...
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