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Unformatted text preview: cos . Hence the Frictional Force is f = N = m g cos Applying Newtons second law to the skier along the incline yields s F = m g sin  m g cos = m a , or solving For a , a = g [sin  cos ] = (9 . 8 m / s 2 ) [sin26 (0 . 96) cos 26 ] =4 . 15981 m / s 2 . To fnd how Far the slope the skier travels beFore stopping, use the kinematic equation v 2 = v 2 + 2 a d . Setting v = 0 and solving For d , d =v 2 2 a =(37 m / s) 2 2 (4 . 15981 m / s 2 ) = 164 . 551 m ....
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This note was uploaded on 02/20/2011 for the course PHYS 1062 taught by Professor Mackie during the Spring '11 term at Temple.
 Spring '11
 MACKIE
 Physics

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