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Unformatted text preview: . 713 m and moment oF inertia 1 2 M r 2 is used to lower a bucket with a mass oF 1 . 8 kg into a well. The bucket starts From rest and Falls For 3 . 4 s. r M m What is the linear acceleration oF the Falling bucket? The acceleration oF gravity is 9 . 8 m / s 2 . Correct answer: 3 . 83478 m / s 2 . Explanation: Let : M = 5 . 6 kg , r = 0 . 713 m , m = 1 . 8 kg , and g = 9 . 8 m / s 2 . Let T be the tension in the cord and α the angular acceleration oF the wheel. Newton’s equation For the mass m is m gT = m a T = m ( ga ) and For the disk T r = I α ( m gm a ) r = p 1 2 M r 2 P ± a r ² 2 m g2 m a = M a 2 m g = ( M + 2 m ) a boland (kbb544) – CW11 – mackie – (10611) 2 a = 2 m g M + 2 m = 2 (1 . 8 kg) (9 . 8 m / s 2 ) 5 . 6 kg + 2 (1 . 8 kg) = 3 . 83478 m / s 2 ....
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This note was uploaded on 02/20/2011 for the course PHYS 1062 taught by Professor Mackie during the Spring '11 term at Temple.
 Spring '11
 MACKIE
 Physics, Mass

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