HW2 - boland (kbb544) – HW2 – Mackie – (10611) 1 This...

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Unformatted text preview: boland (kbb544) – HW2 – Mackie – (10611) 1 This print-out should have 19 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 (part 1 of 2) 10.0 points A descent vehicle landing on the moon has a vertical velocity toward the surface of the moon of 24 . 8 m / s. At the same time, it has a horizontal velocity of 54 . 1 m / s. At what speed does the vehicle move along its descent path? Correct answer: 59 . 5134 m / s. Explanation: Let : v v = 24 . 8 m / s , and v h = 54 . 1 m / s . v h v v v θ The speeds act at right angles to each other, so v = radicalBig v 2 h + v 2 v = radicalBig (54 . 1 m / s) 2 + (24 . 8 m / s) 2 = 59 . 5134 m / s . 002 (part 2 of 2) 10.0 points At what angle with the vertical is its path? Correct answer: 65 . 3728 ◦ . Explanation: v h is the side opposite and v v is the side adjacent to the angle, so tan θ = v h v v θ = arctan parenleftbigg v h v v parenrightbigg = arctan parenleftbigg 54 . 1 m / s 24 . 8 m / s parenrightbigg = 65 . 3728 ◦ . 003 (part 1 of 3) 10.0 points A particle starts from the origin at t = 0 with an initial velocity having an x component of 19 m / s and a y component of − 24 . 3 m / s. The particle moves in the xy plane with an x component of acceleration only, given by 2 . 7 m / s 2 . Determine the x component of velocity af- ter 3 . 1 s. Correct answer: 27 . 37 m / s. Explanation: Let : v x = 19 m / s , a x = 2 . 7 m / s 2 , and t = 3 . 1 s . The x component of velocity is v x = v x + a x t = 19 m / s + (2 . 7 m / s 2 ) (3 . 1 s) = 27 . 37 m / s . 004 (part 2 of 3) 10.0 points Find the speed of the particle after 3 . 1 s. Correct answer: 36 . 6006 m / s. Explanation: Let : a y = 0 and v y = − 24 . 3 m / s . The speed v = bardbl vectorv bardbl of the particle is v = radicalBig v 2 x + v 2 y = radicalBig (27 . 37 m / s) 2 + ( − 24 . 3 m / s) 2 = 36 . 6006 m / s . 005 (part 3 of 3) 10.0 points Find the magnitude of the displacement vec- tor of the particle after 3 . 1 s. boland (kbb544) – HW2 – Mackie – (10611) 2 Correct answer: 113 . 462 m. Explanation: vectorr ( t ) = vectorr + vectorv t + 1 2 vectora t 2 ....
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This note was uploaded on 02/20/2011 for the course PHYS 1062 taught by Professor Mackie during the Spring '11 term at Temple.

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HW2 - boland (kbb544) – HW2 – Mackie – (10611) 1 This...

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