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Unformatted text preview: boland (kbb544) HW14 mackie (10611) 1 This printout should have 18 questions. Multiplechoice questions may continue on the next column or page find all choices before answering. NOTE SAT DEADLINE 001 (part 1 of 3) 10.0 points An electric guitars amplifier is at a distance of 4.4 m. Find the intensity of its sound waves when its power output is 0.17 W. Correct answer: 0 . 000698769 W / m 2 . Explanation: Let : r = 4 . 4 m and P = 0 . 17 W . I = P 4 r 2 = . 17 W 4 (4 . 4 m) 2 = . 000698769 W / m 2 . 002 (part 2 of 3) 10.0 points Find the intensity of the sound waves when the amplifiers power output is 0.58 W. Correct answer: 0 . 00238404 W / m 2 . Explanation: Let : P = 0 . 58 W . I = . 58 W 4 (4 . 4 m) 2 = . 00238404 W / m 2 . 003 (part 3 of 3) 10.0 points Find the intensity of the sound waves when the amplifiers power output is 3.6 W. Correct answer: 0 . 0147975 W / m 2 . Explanation: Let : P = 3 . 6 W . I = 3 . 6 W 4 (4 . 4 m) 2 = . 00238404 W / m 2 . 004 (part 1 of 2) 10.0 points The area of a typical eardrum is about 5 . 3 10 5 m 2 . Find the sound power (the energy per sec ond) incident on an eardrum at the threshold of hearing ( 1 10 12 W / m 2 ) . Correct answer: 5 . 3 10 17 W. Explanation: Let : A = 5 . 3 10 5 m 2 and I = 1 10 12 W / m 2 . At the threshold of hearing, I = P A P = I A = ( 1 10 12 W / m 2 )( 5 . 3 10 5 m 2 ) = 5 . 3 10 17 W . 005 (part 2 of 2) 10.0 points Find the sound power incident on an eardrum at the threshold of pain ( 1 W / m 2 ) . Correct answer: 5 . 3 10 5 W. Explanation: Let : I = 1 W / m 2 . At the threshold of pain, P = ( 1 W / m 2 )( 5 . 3 10 5 m 2 ) = 5 . 3 10 5 W . 006 10.0 points Sound level in decibels is defined as 10 log parenleftbigg I I parenrightbigg , where I = 1 10 12 W / m 2 . The decibel scale intensity for busy traffic is 75 dB. Two people having a loud conversation have a deci bel intensity of 70 dB. boland (kbb544) HW14 mackie (10611) 2 What is the approximate combined sound intensity? Correct answer: 4 . 16228 10 5 W / m 2 . Explanation: Let : 1 = 75 dB , 2 = 70 dB , and I = 1 10 12 W / m 2 . I = I 10 / 10 , so the combined sound intensity I is I = I 1 + I 2 = I parenleftBig 10 1 / 10 + 10 2 / 10 parenrightBig = (1 10 12 W / m 2 ) ( 10 7 . 5 + 10 7 ) = 4 . 16228 10 5 W / m 2 ....
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This note was uploaded on 02/20/2011 for the course PHYS 1062 taught by Professor Mackie during the Spring '11 term at Temple.
 Spring '11
 MACKIE
 Physics

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