F10HW6-Review

# F10HW6-Review - HOMEWORK WEEK 6 REVIEW SET 1.136 1 cm 10-3...

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1.136 c. 0.010 mm x -3 10 m 1 mm x -2 1 cm 10 m = 1.0 x 10 -3 cm or 0.0010 cm Also, diameter = 0.010mm x -3 10 m 1 mm x μ -6 1 m 10 m = 10 μ m. Therefore, only 2 blood cells would fit along this diagonal! d. 0.0605 kPa x 3 10 Pa 1 kPa x -2 1 cPa 10 Pa = 6.05 x 10 3 cPa or 6050 cPa e. 130pm x -12 10 m 1 pm = 1.30 x 10 -10 m and 1.30 x 10 -10 m x -9 1 nm 10 m = 0.130nm 2.98 a. Balance: Cl 2 O 7 + H 2 O HClO 4 Balance Cl (appears only once on each side) by writing a two in front of HClO 4 ; this balances the entire equation: Cl 2 O 7 + H 2 O 2HClO 4 b. Balance: MnO 2 + HCl MnCl 2 + Cl 2 + H 2 O First balance O (appears only once on each side) by writing a two in front of H 2 O: MnO 2 + HCl MnCl 2 + Cl 2 + 2H 2 O Finally, balance H and Cl by writing a four in front of HCl to balance the entire equation: MnO 2 + 4HCl MnCl 2 + Cl 2 + 2H 2 O c. Balance: Na 2 S 2 O 3 + I 2 NaI + Na 2 S 4 O 6 First balance S by writing a two in front of Na 2 S 2 O 3 : 2Na 2 S 2 O 3 + I 2 NaI + Na 2 S 4 O 6 Finally, balance Na by writing a two in front of NaI; this balances the entire equation: 2Na 2 S 2 O 3 + I 2 2NaI + Na 2 S 4 O 6 d. Balance: Al 4 C 3 + H 2 O Al(OH) 3 + CH 4 First balance Al with a four in front of Al(OH) 3 , and balance C with a three in front of CH 4 : Al 4 C 3 + H 2 O 4Al(OH) 3 + 3CH 4 Finally, balance H and O with a twelve in front of H 2 O; this balances the entire equation:

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## This note was uploaded on 02/20/2011 for the course CHEM 110 taught by Professor Dr.huston during the Spring '06 term at Pittsburgh.

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F10HW6-Review - HOMEWORK WEEK 6 REVIEW SET 1.136 1 cm 10-3...

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