{[ promptMessage ]}

Bookmark it

{[ promptMessage ]}

Lab 7 Discussion

Lab 7 Discussion - L ab 7 Discussion T he solvents of...

Info iconThis preview shows pages 1–2. Sign up to view the full content.

View Full Document Right Arrow Icon
Lab 7 Discussion The solvents of choice were 100% ethyl acetate and 92:8 ethyl acetate: acetic acid. These solvents were chosen among 4 solvents, the other two being 10:10:1 toluene: ethyl acetate: acetic acid and 60:40 hexane: ethyl acetate. The two solvents were chosen based upon the extent of separation. The hexane and ethyl acetate solvent did not have enough separation, as was indicated by the relatively low R f values. This meant the solvent was not acceptable because the compounds were too polar as a mobile phase. The relative differences in polarity of the compounds were too close to distinguish. The other mixture of toluene, ethyl acetate, and acetic acid did not separate the compounds as well. The caffeine exhibited very little movement. Also, the acetaminophen was split into two, which means it was perhaps reacting with the substance in a way that would make it difficult to identify. The ethyl acetate and ethyl acetate: acetic acid mixture both provided good R f values because they are the least polar of all the solvents. Since the solvent is the mobile phase, it is ideal to have a nonpolar solvent. The relative polarity of the compounds is therefore able to be determined because the order determined by molecular polarity will be constant.
Background image of page 1

Info iconThis preview has intentionally blurred sections. Sign up to view the full version.

View Full Document Right Arrow Icon
Image of page 2
This is the end of the preview. Sign up to access the rest of the document.

{[ snackBarMessage ]}