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Unformatted text preview: • Angle between F and AC: 90⁰-30⁰ = 60⁰ Using law of sines: • FAB = 10*sin(60)/sin(110) = 9.21 N • FAC = 10*sin(10)/sin(110) = 1.85 N F = 10 N FAB = 9.21 N FAC = 1.85 N 10⁰ 60⁰ 110 ⁰ 2/23/11 x y FO1 = 50 N FO2 = 37.5 N FO3 = 45 N FM FM 60⁰ 30⁰ 45⁰ 59.741⁰ α α If α = 20⁰, what must FM be greater than such that the UM team is winning? How does the FM necessary change with α? Why? What would be the angle to minimize force exerted? UM and Ohio State students are playing tug of war. Each player pulls on his/ her own rope that is connected in the middle. Four Ohio State players have positioned themselves as shown and are pulling with known forces. Two UM students have positioned themselves at angles equidistant from the center line and decide to pull with equal force. FO4 = 35 N...
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This note was uploaded on 02/21/2011 for the course MSE 231 taught by Professor Bedford during the Spring '10 term at University of Michigan.
- Spring '10