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Unformatted text preview: =1normdist(.6333,.5,sqrt(.5*.5/60),1) =1binomdist(37,60,.5,1) o Chapter Exercises 9.62 The excel formula is =1normdist(485/500,.95,sqrt(.95*.5/500),1)=0.258 No, not enough evidence to support exceeding the goal. o Chapter Exercises 9.64 Do not reject the null hypothesis. The decision rule is If test stat exceeds 1.711 we reject the null hypothesis. t=(275.66250)/(78.11/sqrt(5)) = 1.643 Close decision, test stat is close to crital value....
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 Spring '08
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