Unformatted text preview: • =1normdist(.6333,.5,sqrt(.5*.5/60),1) • =1binomdist(37,60,.5,1) o Chapter Exercises 9.62 • The excel formula is =1normdist(485/500,.95,sqrt(.95*.5/500),1)=0.258 • No, not enough evidence to support exceeding the goal. o Chapter Exercises 9.64 • Do not reject the null hypothesis. The decision rule is If test stat exceeds 1.711 we reject the null hypothesis. t=(275.66250)/(78.11/sqrt(5)) = 1.643 • Close decision, test stat is close to crital value....
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This note was uploaded on 02/21/2011 for the course RES 342 taught by Professor Carey during the Spring '08 term at University of Phoenix.
 Spring '08
 CAREY

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