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Unformatted text preview: ECE600 Introduction to Digital Signal Processing Winter 2011 Homework #3 Jan. 28, 2011 HOMEWORK SOLUTIONS #3 1. (a) When f0=1 , the effective discrete frequency = 2 Tf = 0 . 2 rad/sample, which means that the phasor progresses counterclockwise by . 2 2 = 0 . 1 revolutions per sample. (b) When f0=11 , the effective discrete frequency = 2 Tf = 2 . 2 rad/sample, which means that the phasor progresses counterclockwise by 2 . 2 2 = 1 . 1 revolutions per sample. How ever, 1 . 1 revolutions per sample looks the same as 0 . 1 revolutions per sample, because it is impossible to see that the phasor made a complete revolution between samples. (c) When f0=1 , the effective discrete frequency = 2 Tf = . 2 rad/sample, which means that the phasor progresses clockwise by . 2 2 = 0 . 1 revolutions per sample. (d) When f0=9 , the effective discrete frequency = 2 Tf = 1 . 8 rad/sample, which means that the phasor progresses counterclockwise by 1 . 8 2 = 0 . 9 revolutions per sample. However, this looks the same as the previous case, because 0 . 9 revolutions counterclockwise is equivalent...
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This note was uploaded on 02/21/2011 for the course ECE 600 taught by Professor Clymer,b during the Spring '08 term at Ohio State.
 Spring '08
 Clymer,B
 Digital Signal Processing, Frequency, Signal Processing

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