HW 7 Solutions

HW 7 Solutions - Due 11/24/2004, Wed EE323 Homework 7-...

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Due 11/24/2004, Wed 1 EE323 Homework 7--- Solution, Au/2004 5.79 (25 points) (a) (5 points) 2 1 10 , 2 5 1.6 2 1.8 0, 0.7 0.7 BE C BB E E B B E II m A I VV V V V V V V β α =∞ = === =− ×= == ==− = (b) (5 points) 4 3 0.7 ( 5) 4.3 0.7 1.9545 2.2 2.2 5 1.6 5 1.6 1.9545 1.8727 EBB E E E VVV V I m A I VI V −− = = = × = (c) (5 points) Similar to part (b): 65 0 , 0.7 E V V V = and: 7 0.7 ( 5) 5 1.6 5 1.6 1.8727 2.2 E V × = (d) (5 points) For this pnp transistor, 0.7 EB E B V V =−= . 8 8 9 0 1.2 1.2 0.7 1.9 5 51 . 9 3 . 1 0.9394 3.3 3.3 3.3 5 5.1 0.2091 E EC C I V V V V Im A I V = = =+ = = = = = =− + (e) (5 points) For this pnp transistor, 0.7 EB = : () 10 11 10 11 12 150 5 5 ( 5) 5 6.224 1.224 150 91 0.7 1.924 5 0.9321 3.3 5 5.1 0.2463 C V V m A VIV − − = + =+ = = 5.124 (30 points) (1) (5 points) 1, 0 B I = : 100 15 7.5 7.5 0.7 6.8 100 100 B B E V V V V V = = = + Therefore 6.8 1 6.8 E CE E V V I A RK = =
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Due 11/24/2004, Wed 2 (2) (15 points) The small-signal equivalent circuit is: B E e i α C R C 2 o v i v 100 K 100 K e r e i 1 o v 6.8 E RK =Ω b v 1 1 2 2 b e io EE eE eo e E i i eE bi iC o C oC e C i eEeE i v i vv RR rR iv i R v v rR vR v R i R v rR rR αα = + = == = ++ + = −− =−
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This note was uploaded on 02/21/2011 for the course ECE 205 taught by Professor Hemami during the Spring '08 term at Ohio State.

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HW 7 Solutions - Due 11/24/2004, Wed EE323 Homework 7-...

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