HW 8 Solutions

HW 8 Solutions - Due Mon EE323 Homework 8 Solution Au/2004...

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Due 11/29/2004, Mon 1 EE323 Homework 8--- Solution, Au/2004 10.25 (20 points) For PDN, () YAB CD =+ + , which can be drawn directly; and then the PUN as direct dual. So the complete CMOS circuit is: A B C Y DD V A C D D DD V 10.27 (40 points) PUN: YA BA B PDN: B ABAB =+= + + DD V DD V A B B A Y A B A B Y
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Due 11/29/2004, Mon 2 4.105 (40 points) (a) (10 points) When OO L vV = , the output resistance is obtained using eq. (4.140): () ( ) 1 1 6 120 10 1.5 3 0.7 2.4155 DSN n DD tn n W rk V V K L ⎡⎤ ⎛⎞ =− = × × × = ⎜⎟ ⎢⎥ ⎣⎦ ⎝⎠ when H = , the output resistance is obtained using eq. (4.141): 1 1 6 60 10 3 3 0.7 2.4155 DSP p DD tp p W V V K L = × × × = (b) (10 points) We should first figure out the incremental current with respect to the voltage: 2 1 ( ) 2 DN DN n GSN tn n GSN t nn GSN dI WW I kV V V Ld V L ′′ Then the max. current is obtained when the output/drain voltage change is 0.1V:
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HW 8 Solutions - Due Mon EE323 Homework 8 Solution Au/2004...

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