HW4 Solutions

# HW4 Solutions - Due 11/10/2004, Wed EE323 Homework 4-...

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Due 11/10/2004, Wed 1 EE323 Homework 4--- Solution, Au/2004 4.7 (25points) (5 points) 11 32 9 42 3 2 6 2 3.45 10 1.725 10 / 20 10 650 10 ( / ) 1.725 10 / 112.1 10 / 112.1 / ox ox ox nn o x CF m t kC m V s F m F V s A V ε µµ −− × == = × × × × × = × = (a) (5 points) 1 5 0.8 4.2 DS GS t vV v V VV V =< = − = , in the triode region: 26 11 ( ) 112.1 10 10 (5 0.8) 4.15 22 Dn G St D S D S W ik v v m A L ⎡⎤⎡ =− = × × × = ⎢⎥⎢ ⎣⎦⎣ (b) (5 points) 1.2 2 0.8 1.2 DS GS t v V V V V = −= , at the edge of saturation region: 2 ( ) 112.1 10 10 (2 0.8) 0.8 G S t W v V m A L = × × × × = (c) (5 points) 0.2 5 0.8 4.2 DS GS t v V V V V = , in the triode region: ( ) 112.1 10 10 (5 0.8) 0.2 0.04 0.92 G D S D S W v v m A L = × × × × × = (d) (5 points) 55 0 . 8 4 . 2 DS GS t v V VVV =>− = , in the saturation region: 2 ( ) 112.1 10 10 (5 0.8) 9.9 G S t W v V m A L = × × × × = 4.11 (20 points) (a) ( 10 points ) Method 1: Use Eq (4.13) on page 250: 12 2 2 21 1 1000 3.5 200 1.5 1 DS GS t GS GS DS GS t rV V V V = = = Method 2: also use Eq (4.13) [] () 1 1 1 1 1 1 [ ( )] ( ) 500 500 2 . 5 3 . 5 200 D S n G n D S G GS t n DS WW r k

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## This note was uploaded on 02/21/2011 for the course ECE 205 taught by Professor Hemami during the Spring '08 term at Ohio State.

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HW4 Solutions - Due 11/10/2004, Wed EE323 Homework 4-...

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