# HW6 - 13 00 010 110 00 1 0 0 0 0 1 0 14 01 000 011 00 1 0 0...

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1 ECE 662 (Sp 2009) Homework 6- Solution Problem 1(a) Field F1 F2 F3 F4 F5 F6 F7 F8 F9 F10 F11 # of Bits 2 3 3 2 1 1 1 1 1 1 1 State 0 01 000 001 00 0 0 0 0 0 0 0 1 00 000 000 01 0 0 0 0 0 0 0 2 00 101 111 00 0 0 0 0 0 0 0 3 00 110 001 00 0 1 0 0 1 0 0 4 00 001 110 00 1 0 0 0 0 0 0 5 01 000 001 00 0 0 0 0 0 0 0 6 00 000 000 01 1 0 0 0 0 0 0 7 00 110 001 00 0 1 0 0 1 0 0 8 00 001 110 00 0 0 0 0 0 0 0 9 01 000 111 00 0 0 0 0 0 0 0 10 00 000 000 01 0 0 0 0 1 0 0 11 11 000 111 00 0 0 0 0 0 0 0 12 00 110 010 00 0 0 0 1 1 0 1
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Unformatted text preview: 13 00 010 110 00 1 0 0 0 0 1 0 14 01 000 011 00 1 0 0 0 0 0 0 15 00 001 111 00 1 0 0 0 0 0 0 Problem 1 (b) Inputs Outputs State Ti IR 15 IR 14 IR 13 IR 12 BAG3 BAG2 BAG1 BAG0 Next State T 4 0 0 0 1 1/0 1/1 1/0 0/1 T 14, T 5 T 6 0 0 1 0 1/0 1/1 1/1 1/1 T 15, T 7 T 13 X X X X 0 0 0 0 T T 14 X X X X 1 0 1 0 T 10 T 15 X X X X 0 0 0 0 T BAG3 = IR 15 IR 14 IR 13 IR 12 T 4 + IR 15 IR 14 IR 13 IR 12 T 6 +T 14 BAG2 = T 4 +T 6 BAG1 = IR 15 IR 14 IR 13 IR 12 T 4 + T 6 +T 14 BAG0 = ( IR 15 + IR 14 + IR 13 + IR 12 )T 4 + T 6...
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## This note was uploaded on 02/21/2011 for the course ECE 662 taught by Professor Orin,d during the Winter '08 term at Ohio State.

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