Unformatted text preview: to the 6 male positions, and similarly 6! ways of positioning the 6 females. The total number of arrangements is thus 6! × 6!. The basic counting principle applies because for each arrangement of the 6 males, there are 6! ways to arrange the 6 females. 6. Problem 6. This is similar to the birthday problem. There are 15 × 14 × 13 × ... × 6 = 15! 5! ways of all 10 passengers getting oﬀ the bus at 10 diﬀerent bus stops. The total number of possibilities that 10 passengers get oﬀ the bus at any of the 15 stops is 15 10 . Then the probability that no two people get oﬀ at the same bus stop equals 15 × 14 × 13 × ... × 6 15 10 1...
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 Fall '08
 Zahrn
 Probability theory, Bus stop

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