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Unformatted text preview: Kevin Lee Period 5 4/15/10 Chapter 12,13,15 Scrapbook Chapter 12 In this picture my cousin is trying to lift the cart off the track and when he lifts the edge of the cart and stands still, the whole system (cousin's body and the cart) is in static equilibrium. We can observe that the vector sum of all the forces acting on the cart is zero. There are three vector components, in the x, y, and z direction (3-dimensional). This equilibrium tells us that the vector sum of the torques acting on the cart about any point is zero also. Torque can be calculated by crossing the position vector of the cart and the force perpendicular to the vector that my cousin is exerting on the cart. Also, the center of gravity of the cart would be the same as the center of mass if the gravitational acceleration is the same for all parts of the cart. Chapter 13 In this picture, I am standing on top of the Empire State Building. The gravitational force between me and the person behind me taking a picture can be found by multiplying our mass and dividing by the...
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This note was uploaded on 02/22/2011 for the course ASIAN STUD 5A taught by Professor Laveck,k during the Spring '06 term at University of California, Berkeley.
- Spring '06