Lect21 - Physics 212 Lecture 21 35 30 25 20 15 10 5 0...

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Physics 212 Lecture 21, Slide Physics 212 Lecture 21, Slide 1 Physics 212 Physics 212 Lecture 21 Lecture 21 0 5 10 15 20 25 30 35 Avg Avg = 2.6 = 2.6 Confused Confused Confident
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Physics 212 Lecture 21, Slide Physics 212 Lecture 21, Slide 2 Peak AC Problems • “Ohms” Law for each element –V gen = I Z Resistor = I R inductor = I X L Capacitor = I X C • Typical Problem A generator with peak voltage 15 volts and angular frequency 25 rad/sec is connected in series with an 8 Henry inductor, a 0.4 mF capacitor and a 50 ohm resistor. What is the peak current through the circuit? L X L ω = () 2 2 LC ZRX X =+ 1 C X C = 07 L R C 200 L X L == Ω 1 100 C X C Ω 2 2 112 X = +− = Ω 0.13 Amps gen V I Z
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Physics 212 Lecture 21, Slide Physics 212 Lecture 21, Slide 3 Peak AC Problems • “Ohms” Law for each element –V gen = I Z Resistor = I R inductor = I X L Capacitor = I X C • Typical Problem A generator with peak voltage 15 volts and angular frequency 25 rad/sec is connected in series with an 8 Henry inductor, a 0.004 Farad capacitor and a 50 ohm resistor. What is the peak current through the circuit? Which element has the largest peak voltage across it? A) Generator E) All the same. B) Inductor C) Resistor D) Capacitor = max max VI X 12 L R C L X L ω = () 2 2 LC ZRX X =+ 1 C X C = 200 XL = 1 100 C X C = 2 2 112 L C X = +− = Ω 0.13 Amps gen V I Z == BB BB
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Physics 212 Lecture 21, Slide Physics 212 Lecture 21, Slide 4 Peak AC Problems • “Ohms” Law for each element –V gen = I Z Resistor = I R inductor = I X L Capacitor = I X C • Typical Problem A generator with peak voltage 15 volts and angular frequency 25 rad/sec is connected in series with an 8 Henry inductor, a 0.4 mF capacitor and a 50 ohm resistor. What is the peak current through the circuit? What happens to the impedance if we decrease the angular frequency to 20 rad/sec? A) Z increases B) Z remains the same C) Z decreases ω = 25 : (X L -X C ) 2 = (200-100) 2 ω = 20 : (X L -X C ) 2 = (160-125) 2 14 L R C L X L ω = () 2 2 LC ZRX X =+ 1 C X C = 200 L XL = 1 100 C X C = 2 2 112 L C X = +− = Ω 0.13 Amps gen V I Z == BB
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Physics 212 Lecture 21, Slide Physics 212
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Lect21 - Physics 212 Lecture 21 35 30 25 20 15 10 5 0...

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