problem_pdf - armington (kma786) – 8.1 – Stepp –...

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Unformatted text preview: armington (kma786) – 8.1 – Stepp – (55860) 1 This print-out should have 6 questions. Multiple-choice questions may continue on the next column or page – find all choices before answering. 001 10.0 points Evaluate the definite integral I = integraldisplay e 1 x 4 ln x dx. 1. I = 4 25 e 5 2. I = 1 25 (4 e 5- 1) 3. I = 1 5 (4 e 5 + 1) 4. I = 1 5 (4 e 5- 1) 5. I = 1 25 (4 e 5 + 1) 002 10.0 points Evaluate the definite integral I = integraldisplay e 1 parenleftBig 3(ln x ) 2- 2 parenrightBig dx. 1. I = e- 5 2. I = 2 e- 4 3. I = e + 4 4. I = 2 e + 4 5. I = e- 4 6. I = 2 e- 5 003 10.0 points Determine the integral I = integraldisplay ( x 2- 3) sin2 x dx . 1. I = 1 2 x 2 sin2 x- x cos 2 x + 5 2 sin 2 x + C 2. I = 1 4 parenleftBig 2 x sin 2 x +(2 x 2- 7) cos 2 x parenrightBig + C 3. I = 1 4 parenleftBig 2 x cos 2 x +(2 x 2- 7) sin 2 x parenrightBig + C 4. I = 1 4 parenleftBig 2 x sin 2 x- (2 x 2- 7) cos 2 x parenrightBig + C 5. I =- x 2 cos 2 x + x sin 2 x- 5 2 cos 2 x + C 6. I = 1 2 parenleftBig...
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This note was uploaded on 02/21/2011 for the course M 408S taught by Professor Stepp during the Spring '11 term at University of Texas at Austin.

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problem_pdf - armington (kma786) – 8.1 – Stepp –...

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